Question

Assalamualaikum hru all please reply it's urgent I've to submit my work using the substitution method solve each of the following pairs of simultaneous equation 5x+7y=11. 4x-y=2​

Answer 1

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Answer 2

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Given equations :-

5x + 7y = 11                 . . . (i)

4x - y = 2                    . . . (ii)

Solving by substitution method :-

In eq. (ii), we get :-

$\sf{4x = 2+y}\\\\\sf{\implies x=\dfrac{2+y}{4} }$

Now, putting the value of x in eq. (i) :-

$\sf{5x+7y=11}\\\\\sf{\implies 5 \bigg(\dfrac{2+y}{4}\bigg)+7y=11}\\\\\sf{\implies \dfrac{10+5y}{4}+7y=11 }\\\\\sf{\implies \dfrac{10+5y+28y}{4}=11 }\\\\\sf{\implies 10+33y=44}\\\\\sf{\implies 33y=44-10}\\\\\sf{\implies 33y=34}\\\\\boxed{\sf{\implies y= \dfrac{34}{33}}}$

$\rule{130}1$

Again,

$\sf{\implies x=\dfrac{2+y}{4} }\\\\\sf{\implies x= \dfrac{2+\frac{34}{33} }{4} }\\\\\sf{\implies x= \dfrac{\frac{66+34}{33} }{4} }\\\\\sf{\implies x=\dfrac{\frac{100}{33} }{4} }\\\\\boxed{\sf{\implies x=\dfrac{25}{33} }}$

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