Question

Assertion: 29/625 is a terminating decimal fraction Reason: If q= 2^n x 5^m where m, n are non -negative integers then p/q is a terminating decimal fraction.​

Answer 1

Answer:

Correct Answer is Option (a) Since the factors of the denominator 625 is of the form 20 x 54. 29/625 is a terminating decimal Since, assertion follows from reason.

Answer 2

Given,

Assertion: 29/625 is a terminating decimal fraction.

Reason: If q= 2^n x 5^m where m, n are non -negative integers then p/q is a terminating decimal fraction.​

Solution,

Assertion: 29/625 is a terminating decimal fraction.

$\[\begin{array}{l} = \frac{{29}}{{625}}\\ = 0.0464\end{array}\]$

In this limited terms are present after decimal so it is a terminating decimal fraction.

Hence assertion is correct.

Reason: If q= 2^n x 5^m where m, n are non -negative integers then p/q is a terminating decimal fraction.​

$\[\frac{p}{q} = \frac{{29}}{{625}}\]$

Compare the fraction,

$\[p = 29,q = 625\]$

$\[\begin{array}{l}q = 625\\ \Rightarrow q = {2^0} \times {5^4}\end{array}\]$

Compare it with $\[{2^n}{5^m}\]$

$\[m = 4,n = 0\]$

Hence m and n are non- negative integers.

So reason is also correct.