Assertion : 3x2 + x – 1 = (x-1)(3x-2) + 1 Reason : If P(x) and g(x) are two polynomials such that degree of p(x) ≥ degree of g(x)and g(x) ≥0 then we can find polynomials q(x)and r(x) such that P(x) = g(x) q(x) + r(x), where r(x) = 0 of degree r(x) < degree of g(x).
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It's Miss Fairchild," he said, with a smile. "I'll ask you to excuse the other hand; "it's otherwise engaged just at present." b) What changes were seen in the lady as a result of this statement made by the speaker? (3) number should we multiply (25) so that the product may be equal to (2-')?
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Correct option is C)
Let p(x) and g(x) be two polynomials
If g(x) is any polynomial then it can divide p(x) by q(x) where 0<q(x) and may get a remainder say r(x).
If g(x) perfectly divides p(x) by q(x), then r(x)=0.
It is obvious that deg r(x)<deg g(x).
∴ we can find polynomial q(x) and r(x) such that
p(x)=q(x)q(x)+r(x), where r(x)=0 or deg r(x)<deg g(x)
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