Chemistry, asked by alokpatel93, 7 months ago

Assertion (A) 10000 molecules
of CO, have the same volume at
STP as 10000 molecules of CO
at STP.
Reason (R) Both CO and CO2
are formed by combustion of
carbon in the presence of
oxygen.​

Answers

Answered by anish26dhaka
2

Answer:

AT STP, 1 mole of any element / compound occupies 22.4l

∗ 14g of N

2

=0.5 mole of N

2

Molecular weight of N

2

=28g

∴ it occupies 22.4l×0.5=11.2l

∗ 22g of CO

2

molecular weight of CO

2

=12+2×16=44gm

∴ moles of CO

2

=

44

22

=0.5

∴ it occupies 0.5×22.4=11.2l

∗ 32g of SO

2

molecular weight of SO

2

=32+16×2=64g

∴ moles of SO

2

=

64

32

=0.5

∴ volume occupies =0.5×22.4=11.2l

∗ 32gm of O

2

molecular weight of O

2

=16×2=32g

∴ no. of moles of O

2

=

32

32

=1

∴ volume occupied =1×22.4=22.4l

Explanation:

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Answered by raginikri2007
1

Answer:

Assertion (A) 10000 molecules

of CO, have the same volume at

STP as 10000 molecules of CO

at STP.

Reason (R) Both CO and CO2

are formed by combustion of

carbon in the presence of

oxygen.

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