Assertion (A): A chord of a circle of radius 20 cm subtends a right angle at the centre. The area of the minor segment formed is 114 sq.cm. Reason (R): Area of minor segment = Area of circle – Area of sector.
Answers
Answered by
0
Answer:
Area of the minor segment = {pi x 90/360 - sin 45 x cos 45 } * r * r
[ 3.14 x1/4 - 1÷√2 ×1÷√2 } × 20 × 20
= { 3.14 × 1/4 - 1÷2 } × 400
= 3.14 × 400 4-400 2
= 3.14 × 100 - 200
= 314-200
=114
Area of circle = = pixr xr
= 3.14 x 20 x 20
= 3.14 × 400
= 1256
Area of major segment of minor segment = area of circle - area
= 1256 - 114
=1142✓✓✓✓
Similar questions