Question

Assertion (A) :If three vertices of a parallelogram taken in order are (-1,-6), (2,-5) and (7,2), then its fourth vertex is (4,1). Reason (R) :Diagonals of a parallelogram bisect each other. ​

Answer 1

Answer:

Step-by-step explanation:

mark brainliesr

Answer 2

Answer:

Correct option is

A

(1,4)

Let A(−1,−6),B(2,−5),C(7,2) and D(x,y).

AC and BD are diagonals.

So, we know that the diagonals bisect each other in parallelogram, so the diagonals are divided in ratio 1:1.

Mid-point co-ordinates of AC= Mid-point co-ordinates of BD.

⇒ (

2

−1+7

,

2

−6+2

)=(

2

2+x

,

2

−5+y

)

⇒ (3,−2)=(

2

2+x

,

2

−5+y

)

Now, comparing co-ordinates

⇒ 3=

2

2+x

⇒ 6=2+x

⇒ x=4

⇒ Now, −2=

2

−5+y

⇒ −4=−5+y

⇒ y=1

∴ The co-ordinates of fourth vertex of parallelogram D(4,1).