Question

Assertion : A tiger can accelerate from rest at the rate of 4m/s2



Reason : The velocity attained by it in 10 s is 40m/s.

is reason the correct explanation of assertion???​

Answer 1

Given,

Assertion : A tiger can accelerate from rest at the rate of 4m/s²

Reason : The velocity attained by it in 10 s is 40m/s

To find,

Whether the given reason is the correct explanation for the given assertion, or not.

Solution,

From the assertion part we get the following data :

Initial velocity (u) = 0 m/s (starts from rest)

Acceleration (a) = 4 m/s²

Now, according to the kinematics, we know that,

$a = \frac{v - u}{t}$

Here,

a = acceleration

v = final velocity

u = initial velocity

t = time

From the reason part we get the following data :

Time (t) = 10 s

Final velocity (v) = 40 m/s

If the values of time and final velocity given in the reason, along with the values of acceleration and initial velocity given in the assertion, satisfy the previously mentioned equation, then we can conclude that the given reason is correct explanation of the given assertion.

By putting the given values, we get :

$a = \frac{(v - u)}{t}$

LHS of the equation = 4

RHS of the equation :

$= \frac{(40 - 0)}{10}$

$= 4$

So, RHS = LHS

Thus, equation is satisfied by the data taken from assertion part and reason part.

Hence, reason is the correct explanation of the assertion.

Answer 2

Reason is the correct explanation for assertion.

Explanation:

• Whenever a body starts from different velocity and ends up in different velocity, there is a change in motion, and force comes into paly because of acceleration.
• Here, tiger undergoes a non-uniform motion because velocity is not constant.
• Acceleration is the rate of change in velocity with respect to time.
• It is expressed in $m/s^{2}$.
• When a body moves with an initial velocity of $u$ and achieves a final velocity of $v$ in a duration of time $t$, then the acceleration $a$ is given as:
• $a=\frac{v-u}{t}$
• Here, initial velocity $u$ is $0 m/s$.
• So, when final velocity is $v=40 m/s$ in time duration $t=10s$,
• $a=\frac{40-0}{10} =4m/s^{2}$
• So, the acceleration of tiger is $4m/s^{2}$.