Question

Assertion: Copper is kept open in air, it slowly loses its shining brown surface and gains a green coating
Reason: Copper is highly reactive metal.

Answer 1

Answer:

Both the statements are correct and the reason is the correct explanation of the assertion.

Explanation:

• Typically, metals are reactive.

• When exposed to air, the pure copper metal begins to interact with gases such as carbon dioxide and water vapor.

• Copper carbonate and other compounds are created as a result of this.

• The gleaming copper metal turns dull and greenish in color when exposed to copper carbonate.
• The actual reaction takes place as follows:

$\mathrm{2Cu+H_2O+CO_2+O_2\rightarrow Cu(OH)_2+CuCO_3}$                   (1)

Where,

Cu=copper

H₂O=water

CO₂=carbon dioxide

O₂=oxygen

Cu(OH)₂=copper (II) hydroxide

CuCO₃=copper (II) carbonate

So, both the statements are correct and the reason is the correct explanation of the assertion.

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Answer 2

Answer:

The correct answer to this question is Both the statements are correct and the reason is the correct explanation of the assertion.

Explanation:

The actual reaction takes place as follows:

$Copper + Oxygen → Copper (II) oxide2Cu + O2 → 2CuO$

Where,

$Cu=copper$

H2O= water

CO₂=carbon dioxide

O₂=oxygen

Cu(OH)₂=copper (II) hydroxide

CuCO₃=copper (II) carbonate

When copper is placed in a flame with oxygen, the flame changes colour to a bright green. The copper (II) oxide that results is black and insoluble in water.

Copper metal is stable in air under normal conditions. At read heat, copper metal and oxygen react to form Cu2O.

$4Cu(s) + O2(g) → 2Cu2O(s)$

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