Question

Assertion : In diamond each carbon atoms has a tetrahedral environment. Reason : In diamond each carbon atom in its exited state undergoes sp3 hybridisation. a) Both A and R are true and R is correct explanation to A b) Both A and R are true and R is not correct explanation to A c) A is true but R is false d) Both A and R are false

Answer 1

Heya,

The answer is (a).

In diamond, each carbon atom are in a tetrahedral environment because each diamond in excited state have sp3 hybridisation.

Answer 2

Solution : The correct answer to the following problem is option a) Both A and R is correct and R is correct explanation to A

• We know that carbon has an atomic number 6 . It has four valence electrons . They have tendency to form covelent bond and form rings and chains . This property of carbon is called catenation. Due to catenation carbon has many allotropic forms both crystalline and amorphous
• Electric configuration of carbon in ground state is $1s^{2} 2s^{2} 2p^{2}$ electronic configuration in exited state is $1s^{2} 2s^{1} 2p^{3}$
• In carbon only s and p orbitals are available for bonding hance it can have only four pairs of electrons.
• Diamond has crystalline form of carbon . In diamond each carbon has $sp^{3}$ hybridization. Each carbon is linked with four other carbon atom in tetrahedron fashion
• This covalent bond is very strong and is very difficult to break it . That's why diamond ae the hardest substance on earth.

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