Question

. Assertion: The point (k, 2- 2k), (-k +1, 2p) and (-4-k, 6 - 2k) are collinear ifle - 1 = 1 Reason: Three points are collinear if AB + BC = AC. ) 2A​

Answer 1

Answer:

Step-by-step explanation:

(−k+1)(2−2k−6+2k)+k(6−2k−2k)+(−4−k)(2k−2+2k)=0

(−k+1)(−4)+k(6−4k)+(−4−k)(4k−2)=0

4k−4+6k−4k  

2

−16k+8−4k  

2

+2k=0

−2k  

2

−k+1=0

2k  

2

+k−1=0

2k  

2

+2k−k−1=0

2k(k+1)−1(k+1)=0

(k+1)(2k−1)=0

k=−1 or k=  

2

1

​