Assertion: the product of (5+√5) and (3-√5) is an irrational number. Reason: the product of two irrational number is always a rational number
Answers
Answer:
assertion is true but reason is false.
Solution :-
Assertion: the product of (5+√5) and (3-√5) is an irrational number
checking,
→ (5 + √5) * (3 - √5)
→ 5 * 3 - 5√5 + 3√5 - √5 * √5
→ 15 - 2√5 - 5
→ 10 - 2√5
now,
- The square root of a non perfect square number is always irrational => √5 is irrational .
- Rational * irrational = Irrational => 2 * √5 = Irrational .
- Rational - Irrational = Irrational => 10 - 2√5 = Irrational .
Therefore, we can conclude that,
- Assertion is True .
Reason: the product of two irrational number is always a rational number .
Example (1) :-
→ √2 = Irrational
So,
→ √2 * √2 = 2
→ Irrational * Irrational = Rational number .
Example (2) :-
→ √2 = Irrational
→ √8 = Irrational
So,
→ √2 * √8 = √16 = 4
→ Irrational * Irrational = Rational number .
Example (3) :-
→ √3 = Irrational
→ √27 = Irrational
So,
→ √3 * √27 = √81 = 9
→ Irrational * Irrational = Rational number .
Therefore, we can conclude that,
- Reason is False .
Learn more :-
prove that √2-√5 is an irrational number
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