Question

Assertion: Two capacitors are connected in series with a battery. Energy stored across then is in inverse ratio of their capacity. Reason: U=1/2qV or UpropqV

Answer 1

Answer:

PHYSICS

Two capacitors of capacities 1μF and CμF are connected in series and the combination is charged to a potential difference of 120V. If the charge on the combination is 80μC, the energy stored in the capacitor of capacity C in μJ is :

October 15, 2019avatar

Ishant Chakravarthi

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VIDEO EXPLANATION

ANSWER

Capacitance 1μF and CμF are connected in series,

∴C

eq

=

1+C

C

Given, V=120V and q=80μC

∵q=C

eq

V

80=

C+1

C

×20

or C=2μF

Energy stored in the capacitor of capacity C

U=

2

1

C

q

2

=

2

1

×

2×10

−6

(80×10

−6

)

2

=

2

1

×

2×10

−6

80×10

−6

×80×10

−6

U=1600μJ

Explanation:

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Answer 2

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

Explanation:

Assertion: Two capacitors are connected in series with a battery. Energy stored across then is in inverse ratio of their capacity.

Reason: U= 1 / 2 qV or U ∝ qV

U = ε^2 / 2 C

U ∝ 1 / C

U = 1/2 q c

Or U ∝ qv

If both Assertion and Reason are true but Reason is not the correct explanation of Assertion.

Thus reason is not correct.