Chemistry, asked by rg2674213, 3 months ago

assign oxidation number of Nah2po4

Answers

Answered by Anonymous

2

Answer:

x –2 Na H2 P O4 Sum of oxidation numbers of various atoms in NaH2PO4 = 1(+1) + 2(+1) + 1(x) + 4(–2) = x – 5 But the sum of oxidation numbers of various atoms in NaH2PO4 (neutral) is zero ∴ x – 5 = 0 or x = +5. Thus, the oxidation number of P in NaH2PO4 = + 5.

Answered by ROHANRAO

2

Sum of oxidation numbers of various atoms in NaH2PO4 = 1(+1) + 2(+1) + 1(x) + 4(–2) = x – 5

But the sum of oxidation numbers of various atoms in NaH2PO4 (neutral) is zero

∴ x – 5 = 0 or x = +5. Thus, the oxidation number of P in NaH2PO4 = + 5.

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