Chemistry, asked by emmanuelnkandu, 1 year ago

Assign oxidation states to atoms underlined in each compound i. (NH4)2HPO4 ii. Na2C2O4 iii. Mg2P2O7 iv. KMnO4

Answers

Answered by danielochich
0
Facts :

Sum of oxidation states of elements in a molecule equals to zero.

That is, the resultant charge in a molecule equals to zero.


Solutions :

1.) (NH₄)₂HPO₄ — The oxidation state of Phosphorus in this :

NH₄ = +1 H = +1 O = - 2 and P = x

2 + 1 - 8 + x = 0

-5 + x = 0

x = +5

Oxidation state of P is thus +5

2.) Na₂C₂O₄ — The oxidation state of C in this

Na = +1 O = - 2 C = x

2 + 2x + - 8 = 0

2x = 6

x = 3

Oxidation state of C is thus +3

3.) Mg₂P₂O₇ — Oxidation state of Phosphorus in this molecule

Mg = +2 O = - 2 P = x

4 - 14 + 2x = 0

2x= 10

x = 5

+5

4.) KMnO₄ — Oxidation state of Mn in this

K = +1 O = - 2 Mn = x

1 - 8 + x = 0

x = +7


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