Assign oxidation states to atoms underlined in each compound i. (NH4)2HPO4 ii. Na2C2O4 iii. Mg2P2O7 iv. KMnO4
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Facts :
Sum of oxidation states of elements in a molecule equals to zero.
That is, the resultant charge in a molecule equals to zero.
Solutions :
1.) (NH₄)₂HPO₄ — The oxidation state of Phosphorus in this :
NH₄ = +1 H = +1 O = - 2 and P = x
2 + 1 - 8 + x = 0
-5 + x = 0
x = +5
Oxidation state of P is thus +5
2.) Na₂C₂O₄ — The oxidation state of C in this
Na = +1 O = - 2 C = x
2 + 2x + - 8 = 0
2x = 6
x = 3
Oxidation state of C is thus +3
3.) Mg₂P₂O₇ — Oxidation state of Phosphorus in this molecule
Mg = +2 O = - 2 P = x
4 - 14 + 2x = 0
2x= 10
x = 5
+5
4.) KMnO₄ — Oxidation state of Mn in this
K = +1 O = - 2 Mn = x
1 - 8 + x = 0
x = +7
Sum of oxidation states of elements in a molecule equals to zero.
That is, the resultant charge in a molecule equals to zero.
Solutions :
1.) (NH₄)₂HPO₄ — The oxidation state of Phosphorus in this :
NH₄ = +1 H = +1 O = - 2 and P = x
2 + 1 - 8 + x = 0
-5 + x = 0
x = +5
Oxidation state of P is thus +5
2.) Na₂C₂O₄ — The oxidation state of C in this
Na = +1 O = - 2 C = x
2 + 2x + - 8 = 0
2x = 6
x = 3
Oxidation state of C is thus +3
3.) Mg₂P₂O₇ — Oxidation state of Phosphorus in this molecule
Mg = +2 O = - 2 P = x
4 - 14 + 2x = 0
2x= 10
x = 5
+5
4.) KMnO₄ — Oxidation state of Mn in this
K = +1 O = - 2 Mn = x
1 - 8 + x = 0
x = +7
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