Question

Assign quantum numbers for the 21st electron in manganese.

Answer 1

Answer:

n=4,l=0,m=0,s=+/-1/2

Explanation

Electronic configuration of Mn is Ar 3d^5 4s^2

therefore according to the outermost shell

n=4

l=0 (s subshell)

m=0

and spin can be 1/2 or -1/2

hope this helps