Question

assign the oxidation number of Fe in K4[fe(CN)6]

Answer 1

oxidation state of CN is -1
, ,, , ,,,, of K is +1


now ,
(+1) x 4 +{ x -6}= 0
+4 +x-6 =0
x=+2

hence oxidation state of Fe = +2

Answer 2

In $K_4[Fe(CN)_6]$, the Fe gets +2 as an oxidation number.

Explanation:

Given:

Compound is $K_4[Fe(CN)_6]$

To find:

Oxidation number of Fe = ?

Calculation:

Let the oxidation number of Fe in $K_4[Fe(CN)_6]$ be 'x'.

WKT the sum of charges of the compound is zero. Thus to find the oxidation of Fe, the following calculation must be done:

As per the formula of the compound, the oxidation number of $K_4$ and 'CN' is 4 and (-6) respectively.

Substituting the value in the following equation:

4(+1) + x + 6(-1) = 0

4 + x - 6 = 0

4 - 6 = -x

-2 = -x

2 = x

Conclusion:

From the above calculation it is inferred that the oxidation number of Fe in $K_4[Fe(CN)_6]$ is +2.

Learn more about such concept

Question 8.2 What are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?

https://brainly.in/question/2161394

The oxidation number of arsenic atom in H3AsO4 is :

(A) –5

(B) +1

(C) –3

(D) +5