Question

assign the oxidation number of Fe in K4[fe(CN)6]

Answer 1

We know,

Oxidation number of K = + 1

Oxidation number of CN = -1

Given compound,

K4[fe(CN)6]

Let x be the oxidation number of Fe

=> 4(+1) + x + 6(-1) = 0

4 + x - 6 = 0

x - 2 = 0

x = + 2

Therefore, oxidation number of Fe = + 2

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