Question

Assign the position of the element having outer electronic configuration (i) ns²np⁴ for n=3 (ii) (n-1)d²ns² for n=4, and (iii) (n-2) f⁷ (n-1)d¹ns² for n=6, in the periodic table.

Answer 1

(1) 16th group,3rd period

(2) 4the group,4th period

(3) 3rd group,6th period

Answer 2

Since n = 3, the component has a place with the third time frame.

It is a p– square component since the last electron possesses the p– orbital.

There are four electrons in the p– orbital. Along these lines, the comparing gathering of the component = Number of s– square gatherings (3s2) + number of d– square gatherings ([Ne] 10 + number of p– electrons (3p4) = 2 + 10 + 4 = 16.