Question

Assignment 1: Find the increase in pressure required to decrease volume of mercury by 0.001 %.

Answer 1

Given :

Decrease in the volume of mercury = 0.001%

Bulk modulus (k) = 2.8×10¹⁰ N/m²

To Find :

The increase in pressure of the mercury

Solution :

• Percentage of decrease in volume    $= \frac{change\:in\:volume}{original\:volume}$

       $\frac{\Delta l}{l} = \frac{0.001}{100}$

       $\frac{\Delta l}{l} = -10^{-5}$

• Bulk modulus of mercury is given by the formula

        $k=\frac{\Delta p}{\frac{-\Delta V}{V} }$

       $\Delta p=k\times \frac{-\Delta V}{V}$

       $\Delta p=-2.8\times 10^{10} \times (-10^{-5})$

       $\Delta p=2.8\times 10^{5}N/m^{2}$

The required increase in the pressur pe of the mercury is 2.8×10⁵ N/m².