Question

Assignment 1
Q.1. Find the number of terns of the exponential series such that their sum gives
the value of el correct to six decimal places at x = 1.​

Answer 1

Answer:

plz write your ques correctly..

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

e^x =( 1) +( x) + (x^2 / 2!) + (x^3 / 3!) + (x^4 / 4!) + ...........................

we know that

                      e^1 = e = 2.71828182

put  x = 1   in equcation

e  =  1 + 1 + (1/2) + (1^2 /2!).....................................

sum of first terms is = 1

sum of first two terms is = 2

sum of first 3 terms is = 2.5

sum of first 4 terms is = 2.66666666

sum of first   5   terms is = 2.70833333

sum of first   6  terms is = 2.71666666

sum of first   7   terms is = 2.71805556

sum of first   8  terms is =  2.71825396

sum of first 9 terms is = 2.71827877

sum of first  10  terms is = 2.71828152

sum of first   11  terms is = 2.718281801

sum of first 12 terms is = 2.71828182

so sum of 12 terms is give correct value up to 8 decimal places

so answer is 12 terms  

                                                                 thankyou !