Question

Assignment - 9.1
1. If 15 men can do a piece of work in 10 days, then how many men are
required to complete it in 50 days?
​

Answer 1

Answer:

Step-by-step explanation:

There is an indirect relationship between men and days which helps to derive a  formula which is as follows,

M1*D1 = M2*D2 (Where M=Men and D=Days, 1&2 are differentiating variables)

So, solving the question through this formula,

Let the number of men required to complete the work in 50 days be equal to x men.

Then,let, M1=15 men

              D1=10 days

              M2=x men

              D2=50 days

Applying all the values to the formula,

15*10 = x*50

x= 15*10/50

x=3

Therefore, number of men required to complete the work in 50 days are 3 men.

PLZ MARK AS BRAINLIEST

Answer 2

Given A can do the work in 10 days ,B can do the work in 12 days and C can do the work in 15 days.
Then A's one day's work =
10
1
​

B's one day's work =
12
1
​

C's one day's work =
15
1
​

Then (A+B +C)'s one day's work =
10
1
​
+
12
1
​
+
15
1
​
=
1800
450
​
=
4
1
​

(A+B+C)'s two days' work =
4
1
​
×2=
2
1
​

But B leaves 3 days before the work gets finished, so C does the remaining work alone
C's 3 days' work =
15
1
​
×3=
5
1
​

Then work done in 2+3 days =
2
1
​
+
5
1
​
=
10
7
​

Work done by B+C together =1−
10
7
​
=
10
3
​

(B + C)'s one day work =
12
1
​
+
15
1
​
=
20
3
​

So number of days worked by B and C together=
10
3
​
×
3
20
​
=2 days
Then total work done =2+3+2=7 days