Math, asked by iamanishkapoor, 8 months ago

Assignment - Cube and Cube Roots 1. Which of the following numbers are perfect cubes? a. 243 b.8000 c.9261 2. Find the volume of a cube whose edge measures 5.3 cm. 3. Find the side of the cube whose volume is 820.584 cubic metres. 4. Find the smallest number by which 2560 be multiplied so that the product becomes a perfect cube. 5. Find the smallest number by which 88209 can be divided so that the quotient is a perfect cube. answer with explination

Answers

Answered by contactaaditjain
3

Answer:

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1. 243 isnt a perfect cube

  8000 is a perfect cube

  9261 is a perfect cube

2.Volume of  a cube whose edge measures 5.3 cm is 148.88cm³

3. the side of the cube whose volume is 820.584 cubic metres is 9.36m

4. If we multiply the number by 5^2=25, the result will be 8^3* 5^3, which is the perfect cube. So 25 is the smallest positive integer.

5. Out of the prime factors of 88209, 11 cannot be considered in its perfect cube as it have only two factors of 11. So, 11×11 is the number by which 88209 must be divided to make the quotient a perfect cube. Hence, the smallest number is 121, which when divides 88209, the quotient is 729 which is a perfect cube.

Step-by-step explanation:

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Answered by niharika9284
1

Step-by-step explanation:

(1) b

(2) 5.3³ = 148.777cm³

(3) a cube whose volume is 830.584cm³ having a side of 9.4cm

(4) factors of 2560 = (2×2×2)×(2×2×2)×(2×2×2)×(5)

so we need to multiple 2560 by (5×5) 25 to make to perfect cube

Therefore smallest number is 25

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