Math, asked by shritija53, 3 months ago

Assignment - Solve the following linear equations with 3
variables using Adjoint method.
2x + 3y + 4z = 12
3x + 10y - 9z = 34
6x + 15y + 10z = 18​

Answers

Answered by rainasaini0001
2

Answer:

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Answered by amitnrw
0

Given :  2x + 3y + 4z = 12

3x + 10y - 9z = 34

6x + 15y + 10z = 18​

To Find : Solve for x , y & z

Solution:

2x + 3y + 4z = 12

3x + 10y - 9z = 34

6x + 15y + 10z = 18​

\left[\begin{array}{ccc}2&3&4\\3&10&-9\\6&15&10\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}12\\34\\18\end{array}\right]

A=\left[\begin{array}{ccc}2&3&4\\3&10&-9\\6&15&10\end{array}\right]

| A | =   2 ( 10 x 10 - (-9)15) - 3 ( 3 x 10 - 6 (-9)) + 4 (3 x 15 - 6 x 10) )

= -142

Adj A  =\left[\begin{array}{ccc}145&-5&-67\\-42&-2&15\\-45&4&11\end{array}\right]

A⁻¹ = adj A / | A|

\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\dfrac{-1}{142} \left[\begin{array}{ccc}145&-5&-67\\-42&-2&15\\-45&4&11\end{array}\right]\left[\begin{array}{ccc}12\\34\\18\end{array}\right]

\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\dfrac{-1}{142}\left[\begin{array}{ccc}194\\-604\\-70\end{array}\right]

x = - 97/71

y = 302/ 71

z = 35/71

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