assume 35.1258* 0.4111=14.4402 if0.0351258*4111*A=0.144402, then what is the value of A
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Correct option is
A
2k
m
v
Assuming the collision to last for a small interval only we can apply the principle of conservation of momentum The common velocity after the collision is
2
v
The kinetic energy =
2
1
(2m)(
2
v
)
2
=
4
1
mv
2
This is also the total energy of vibration as the spring is unstretched at this moment If the amplitude is A the total energy can also be written as
2
1
kA
2
Thus
2
1
kA
2
=
4
1
mv
2
giving A=
2k
m
v
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