Math, asked by rudraptp8082pbqloc, 1 year ago

assume 57+59+109 = 0 , then find the value of 57^3+59^3+109^3 = ?

Answers

Answered by angadgurnoor
3
Let 57=a,59=b, 109=c
If a+b+c=0
Then
a^3+b^3+c^3=3abc=3*57*59*109=1099701
Hope it helps
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