Question

Assume a and b are independent events with p(a)=0.2 and p(b)=0.3 let c that none of the events a and b occurs what is the probability of c the problem belong from which book

Answer 1

Step-by-step explanation:

Given that a and b are independent events

and c is the event that none of the events a and b occur.

Hence P(c) =

P(non occurence of a INTERSECTION non occurence of b)

i.e., P(a bar Intersection b bar)

Since a and b are independent a bar and b bar are also independent.

P(c)= (1-P(a))(1-P(b))

= (1-0.2)(1-0.3)

=0.8×0.7

P(c) =0.56