Question

Assume a company has been contracted to build a fence that's 1 Km long. the fence needs to have pillars every 500 meters, including at both ends. the cost of painting each pillar is $10. The cost of painting the rest of the fence is $160. Cost of painting brush is $10. What was the total cost of the painting job?

Answer 1

Answer:

200

Step-by-step explanation:

cost of painting =( 3 * 10) + 160+10

= 200

Answer 2

Answer:

The total cost of the painting job was $210.

Step-by-step explanation:

Given, a company has been contracted to build a fence and length of the fence is 1 km.

We know, 1 km = 1000 m

Now the fence have pillars every 500 meters, including at both ends

$= \frac{1000}{500} + 2 \\ = 2 + 2 \\ = 4$

It is also given, cost of painting of each pillar is $10

Then cost of 4 pillars is (4×10) = $40

Cost of painting the rest of the fence is 160 and cost of painting brush is 10.

So total cost of painting job

$= (40 + 160 + 10) \\ = 210$

Therefore the total cost of the painting job was $210.

This is a problem of Algebra.

Algebra.Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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