Assume a SNV in HWE. Its heterozygous frequency and one of its homozygous frequency are the same. Answer its minor allele frequency down to two decimal places.
Answers
Answer:
I THE INTUITIVE APPROACH
II THE HARDY-WEINBERG EQUILIBRIUM
II-1 FOR AN AUTOSOMAL, DIALLELE, CO-DOMINANT GENE
EXERCISE
III THE HW LAW
III-1 DEMONSTRATION OF THE LAW
III-2 EXERCISES
III-3 CONSEQUENCES OF THE LAW
III-3.1 WHAT IS THE ALLELE FREQUECY IN THE n+ 1 GENERATION?
III-3.2 WHAT IS THE GENOTYPE FREQUENCY IN THE n+ 1 GENERATION?
III-3.3 EXAMPLE
IV EXTENSION OF HW TO OTHER GENE SITUATIONS
IV-1 TO AN AUTOSOMAL, TRIALLELE, CO-DOMINANT GENE
IV-2 TO AN AUTOSOMAL, DIALLELE, NON CO-DOMINANT GENE
IV-3 TO AN AUTOSOMAL, TRIALLELE, NON CO-DOMINANT GENE
IV-3.1 BERNSTEIN's EQUATION
IV-4 TO A HETEROSOMAL (= gonosomic) GENE
IV-4.1 Y CHROMOSOME
IV-4.2 X CHROMOSOME
V SUMMARY- CONSEQUENCES OF HW's LAW
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I- THE INTUITIVE APPROACH
The Hardy-Weinberg law can be used under some circumstances to calculate genotype frequencies from allele frequences. Let A1 and A2 be two alleles at the same locus,
p is the frequency of allele A1 0 ≤ p ≤ 1
q is the frequency of allele A2 0 ≤ q ≤ 1 and p + q = 1
where the distribution of allele frequencies is the same in men and women, i.e.:
hommes (p,q) femmes (p,q)
if they procreate : (p + q)2 = p2 + 2pq + q2 = 1
where:
p2 = frequency of the A1 A1 genotype <-- HOMOZYGOTE
2pq = frequency of the A1 A2 genotype <-- HETEROZYGOTE
q2 = frequency of the A2 A2 genotyp <-- HOMOZYGOTE
these frequencies remain constant in successive generations.
Example : autosomal recessive inheritance with alleles A and a, and allele frequencies p and q:
--> frequency of the genotypes: : AA = p2 and the phenotypes [ ]: [A] = p2 + 2pq
Aa = 2pq [a] = q2
aa = q2
Explanation:
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