Assume acceleration to be uniform.
A bullet losses 1/n of its velocity in passing through a plank. What is the least number of planks requi
stop the bullet ? (Assuming constant retardation)
A car moving along a straight highway with speed 126 kmh 1 is brought to a halt within a distance of 2
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3
Answer:
I am telling you a short cut formula, where you can directly put the value of n and get the results, see the photo hope you will be able to understand.
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6
Answer:
n^2/2n-1
Explanation:
Since the bullet loses 1/n of its velocity, final velocity = v - v/n = v(n-1)/n
No. of planks = u^2 /(u^2 - v^2)
= u^2/[u^2 - {v(n-1)/n}^2]
= n^2/2n-1
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