Question

Assume air contains 21% oxygen and 79% nitrogen. If air is compressed to 5.5 atm, what is the partial pressure of the oxygen​

Answer 1

Answer:

5

Explanation:

5

Answer 2

Answer: The partial pressure of a gas in a mixture of gases is the pressure that the gas would exert if it were present alone in the container at the same temperature and volume.

Explanation:

In the case of air, which contains 21% oxygen and 79% nitrogen, the partial pressure of the oxygen can be calculated by multiplying the total pressure of the mixture by the proportion of oxygen present.

If air is compressed to 5.5 atm, the partial pressure of the oxygen would be:

Partial Pressure of Oxygen = Total Pressure * Proportion of Oxygen

= 5.5 atm * 0.21

= 1.155 atm

So, if air is compressed to 5.5 atm, the partial pressure of the oxygen would be 1.155 atm.

It is important to note that changes in pressure can affect the behavior of gases, and the partial pressure of a gas in a mixture is directly proportional to its proportion in the mixture. Therefore, as the total pressure of the air mixture increases, the partial pressure of the oxygen would also increase, and vice versa.

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