Question

Assume pupil diameter to be 2.5 mm . Assume light of wavelength 500 nm .What is the minimum distance between two point objects that can be clearly seen when kept at least distance of distinct vision seen

Answer 1

Answer:

Heyyyaa...

The answer is 25 cm.

Answer 2

The minimum distance between two point objects is $6.1\times10^{-5}\ m$

Explanation:

Given that,

Diameter = 2.5 mm

Wave length = 500 nm

Suppose a comfortable viewing distance of 25 cm.

We need to calculate the minimum distance between two point objects

Using formula of minimum distance

$\sin\theta=\dfrac{1.22\lambda}{D}$

$\dfrac{d}{L}=\dfrac{1.22\lambda}{D}$

$d=\dfrac{1.22\times\lambda\times L}{D}$

Where, L = viewing distance

D = diameter

$\lambda$ = wavelength

Put the value into the formula

$d=\dfrac{1.22\times500\times10^{-9}\times25\times10^{-2}}{2.5\times10^{-3}}$

$d=0.000061\ m$

$d=6.1\times10^{-5}\ m$

Hence, The minimum distance between two point objects is $6.1\times10^{-5}\ m$

Learn more :

Topic :  wave length

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