Chemistry, asked by aditrivashishat, 1 month ago

assume that 4g of l2 reacts with 4g of mg as- Mg+l2=Mgl2.Identify limiting reagent and calculate amount of Mgl2 produced.(At mass of mg=24 and l=127)

Answers

Answered by anshika0831

0

Answer:

limiting reagent = I2

MgI2 formed = 4.38g

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