Question

Assume that a car is able to stop with retardation of 5 m/s2. Driver of the car sees an emergency situation and applies the breaks and it took him 0.6 second to apply breaks. If car is moving with speed of 60 km per hour, then what will be the distance covered by the car before stopping?​

Answer 1

Explanation:

Given,

Speed=20m/s,d=50m,retardation=5m/s

2

Let the ppossible reaction time be t

s

So the car moves 20tm And applied breaks with retardation 5m/s

2

So, the total distance under retardation is ≤50m

Thus the distance under the application of retardation =

2×5

20

2

−0

2

=s

′

⇒s

′

=40m

Therefore, 20t

s

+40≤=50⇒20t

s

≤50−40⇒20t

s

=10⇒t

s

≤

2

1

≤0.5s

Answer 2

Hope it helps you mate....