Question

Assume that a pipelining is implemented and the data given are
b = 3; Pj = 0.4; Pt = 0.6;
where
b = jump penalty (loss of cycles due to jump).
Pj = probability that the instruction is a jump.
Pt = probability that the jump is taken.
What will be the average instruction time?​

Answer 1

Explanation:

An average instruction takes 200 ns of CPU time and one memory access. The TLB hit ratio is 80% and page fault ratio is 20%.

Answer 2

The average instruction time will be 0.5

Explanation:

Given:

Jump penalty (loss of cycles due to jump) i.e. b = 3

The probability that the instruction is a jump, i.e. Pj = 0.4

The probability that the jump is taken, i.e. Pt = 0.6

Solution:

The average instruction time will be given by = Pt / (Pj * b)

= 0.6 / (3 * 0.4)

= 0.5

hence, The average instruction time will be 0.5