Assume that f'(3)=-1,g'(2)=5, g(2)=3 and y=f[g(x)] find S'(6)
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hi mate. . . hope this is helpful
Explanation:
(g º f)(x) = g(f(x))
First we apply f, then apply g to that result:
(g º f)(x) = (2x+3)2
What if we reverse the order of f and g?
(f º g)(x) = f(g(x))
First we apply g, then apply f to that result:
(f º g)(x) = 2x2+3.
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