Assume that g=10m/s2 and there is no air resistance. A stone is dropped from rest. What is its speed? a) After 1 second
nabila786:
can you be more precise about the question as to calculate speed you will need height from which the stone is being dropped and also the stones mass (weight).
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Answered by
3
The speed will be 10m/s
using Newton's 1 law
v=u+at
v= 0 + 10*1
Hence velocity after 1 sec is 10m/s....
using Newton's 1 law
v=u+at
v= 0 + 10*1
Hence velocity after 1 sec is 10m/s....
Answered by
6
use kinematics equation ,
v = u + at
v =0 + g× 1 = 10×1 = 10m/s
hence after 1sec velocity of stone =10m/s
v = u + at
v =0 + g× 1 = 10×1 = 10m/s
hence after 1sec velocity of stone =10m/s
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