Question

Assume that gravitational force between earth and its
satellite is inversely proportional to distance r
between them, then
(1) Orbital velocity of satellite will be independent
of r
(2) Orbital velocity of satellite will be proportional to 1/r^1/2

(3) Time period of satellite is proportional to r2
(4) Time period of satellite is proportional to 1/2​

Answer 1

option A

orbital speed is independent of the r

Answer 2

Answer:

orbital velocity of the satellite will be proportional to 1/r^1/2

Explanation:    

The gravitational force between the earth and an object is called the weight of the object.

It is also equal to the product of the acceleration due to gravity and the mass of the object. The weight of any object, w = mg

where

m= is the mass of the object and

g= is the acceleration due to gravity for the earth (g = 9.8 ms²).

The velocity has to be just right, so that the distance of the center of the Earth is always be the same. The orbital velocity of the gravitational force

formula contains a constant, G, which is called the "universal gravitational constant

Its value is = 6.673 x 10-11 N-m²/kg²

let

F= k/r

F=mv²/r

k/r=mv²/r

V=$\sqrt{km}$

Vαm

orbital velocity will be directly proportional to   1/r^1/2

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