Question

Assume that if the earth were made of lead of relative density 11.3, then what would be the value of acceleration due to gravity on the earth surface​

Answer 1

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Answer 2

Dear Student,

◆ Answer -

g = 20.11 m/s^2

● Explaination -

Acceleration due to gravity at surface of earth is -

g = 4π/3 GRd

g = 4×3.142/3 × 6.67×10^-11 × 6.37×10^6 × 11300

g = 20.11 m/s^2

Hence, acceleration due to gravity at surface of earth is 20.11 m/s^2.

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