assume that
![\sqrt{5} \sqrt{5}](https://tex.z-dn.net/?f=+%5Csqrt%7B5%7D+)
is irrational.
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Answer:
√5=(supposed in from of p and q)
√5=a/b
squaring both side
(√5)^2=(a/b)^2
5=a^2/b^2
a^2=5b^2 then
b^2 is division by 5
b is division by 5
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