assume that the brakes of a car produce a maximum retrading force equal to one half of the weight of the car calculate the maximum retradation possible. Assume acceleration due to gravity as 10 m/s^2
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Explanation:
Acceleration due to friction (retardation) (a) = - μg=−0.9×10=−9m/s
2
Final velocity, v=0m/s
Initial velocity, u=20m/s
Applying formula: v
2
=u
2
+2as
Where s is the distance traveled by car before it come to rest.
⇒0
2
=20
2
+2(−9)s
⇒18s=400
⇒s=22.2 m
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