Question

Assume that the electron in Li2+ ion is in third orbit. Calculate the radius of the orbits?

Answer 1

The radius of the third orbit would be
= 0.529 × n²/Z
= 0.529 × 9/ 3
= 1.587 °A

Answer 2

Radius in nth orbit =0.529X$\frac{ n^{2} }{z}$

R=0.529X9/3=1.56A