Assume that the Li ion(+2) charged is in 3rd orbit.Calculate the radius of the orbit and the total energy of the electron?
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radius=0.529(n^2/z)A
and total energy=-13.6 (z^2/n^2)eV/atom
now , radius=0.529x (9/3)=1.587A
total energy =-13.6 (9/9)=-13.6eV/atom
and total energy=-13.6 (z^2/n^2)eV/atom
now , radius=0.529x (9/3)=1.587A
total energy =-13.6 (9/9)=-13.6eV/atom
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