Question

Assume that the object is being pulled along the ground by a 75-N force directed 28° above the horizontal. How much work does the force do in pulling the object 8•0m?

Answer 1

Since the force is not horizontal it will have to additional work to push the object horizontally.

Work efficiency(η) = cos*angle=cos*28° =0.883

F=75N

distance(s)= 80m

A=(F*s)/ η=(75N*80m)/0.883 =6795 J

Answer 2

The work done by the force in pulling the object is 529.76 joules.

Explanation:

It is given that,

Force acting on the object. F = 75 N

Angle above horizontal, $\theta=28^{\circ}$

We need to find the work does the force do in pulling the object 8 m. It is given by :

$W=Fd\ cos\theta$

$W=75\times 8\ cos(28)$

W = 529.76 Joules

So, the work done by the force in pulling the object is 529.76 joules. Hence, this is the required solution.

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