Question

Assume that the visible star and its companion star, which is dark and unseen"

Answer 1

Answer:

Explanation:

Start with the standard expression  

(P/2π)² = a³ / G(M+m)  

G(M+m) = a³ / (P/2π)²  

in which you called T = P in seconds  

Since  

v = 2πa/P ,  

v ³ = (2πa/P)³ .=  

a/v = (P/2π),  

the RHS of the above equation becomes  

a³ / (P/2π)² = (2πa/P)³ [P/2π] = v ³ [P/2π].  

Therefore the above equation becomes  

G(M+m) = v ³ [P/2π],  

(M+m) = [P/2π]v ³ / G.  

Taking care to put all values in SI (metre -kg -seconds) units, by converting speed in m/s, you can evaluate (M+m). As you know one M = m1 = 6.5 X (1.99 x 10³ºkg), you can compute the other m2 = m.

Answer 2

Explanation:

Assume that the visible star and its companion star, which is dark and unseen"

A rubber band wth ball attached is stressed and released find the velocity Assume that the visible star and its companion star, which is dark and unseen"achieved