Question

Assume the ramp in question 25 now has friction. The block only accelerates 1.19 m/s^2 down the ramp. What is the frictional force on the block?
83.06 N
121.9 N
198.7 N
43.01 N

Answer 1

43.01 is the answer.

Hope this will help you.

Answer 2

The frictional force on the block is 83.06 N.

(a) is correct option.

Explanation:

Given that,

Acceleration = 1.19 m/s²

Suppose the mass of block is 20 kg and angle is 31°.

We need to calculate the frictional force on the block

Using balance equation

$ma=mg\sin\theta-f_{k}$

$f_{k}=mg\sin\theta-ma$

Where, m = mass of block

a = acceleration

g = acceleration due to gravity

Put the value into the formula

$f_{k}=20\times9.8\sin31-20\times1.19$

$f_{k}=77.14\ N$

The nearest frictional force will be 83.06 N.

Hence, The frictional force on the block is 83.06 N.

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Topic : frictional force

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