Question

Assuming
According the chiodes are ideal calculate Curre
in do to the craint they knee Corrent of the
ideal zener diode is loma to mount oun 50 across
the minimum value of RL is and the men nom po
of Zener diodes ou
1K
m. M
DL
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Answer 1

Answer:

The Zener diode acts as the voltage regulator in the circuit and the voltage supply is variable hence, excess of voltage over 50 V will be across 5KΩ resistance.

Thus, minimum voltage across 5KΩ resistance is 80 V−50 V=30 V

Current through 5KΩ resistance is I

1

(say)

I

1

=

5000

30

=6 mA

Also, maximum voltage across 5KΩ resistance is 120 V−50 V=70 V

Current through 5KΩ resistance is I

1

′

...(say)

I

1

′

=

5000

70

=14 mA

Now, voltage across load resistance of 10KΩ is 50 V

Thus, current through 10KΩ will be

I

2

=

10000

50

=5 mA

Hence, maximum current through Zener diode is

I

z

=I

1

′

−I

2

=14−5=9 mA

Minimum current through Zener diode is

I

z

=I

1

−I

2

=6−5=1 mA