Question

Assuming all the surface to be frictionless the smaller block m is moving horizontally with acceleration a, and vertically downwards with acceleration 2a then magnitude of net acceleration of smaller block m with respect to ground is - ​

Answer 1

ANSWER

Free body diagram for m

For m,

mg−T=m2a ........(i)

N = ma .......(ii)

Free body diagram for M

For M

2T - N = Ma ...........(iii)

On solving, a=

(M+5m)

2mg

∴ Net acceleration of m,

a

m

=

4a

2

+a

2

=

5

a=

(5m+M)

2

5

mg

solution