Question

assuming are to be solid sphere of uniform density 5800 kg per metre cube and radius 6 into 10 to the power 6 m calculate the value of g on its surface

Answer 1

Answer:

Correct option is

B

9.82ms

−2

.

Here, R=6400×10

3

m=6.4×10

6

m

ρ=5.5g/c.c.=5.5×10

3

kg/m

3

Now, g=

R

2

GM

=

R

2

G

×

3

4

πR

3

×ρ

=

3

4

πGRρ

=

3

4

×

7

22

×6.66×10

−11

×6.4×10

6

×5.5×10

3

=9.82ms

−2

.