Assuming Complete Decomposition,the volume of CO2 released at S.T.P on heating 9.85g BaCO3 will be
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Answer:
Correct option is D) 1.12 L
Explanation:
BaCO3 -----> BaO + CO2
When 197 grams of BaCO3 is decomposed it forms 22.4 litres of CO2
If 9.85 grams of BaCO3 is decomposed it forms X litres of CO2.
X = 9.85 × 22.4
—————— = 1.12
197
Hence volume is 1.12 litres
Hope it helps you
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