CBSE BOARD XII, asked by siddeshgmysore4782, 10 months ago

Assuming complete ionisation the pH of 0.005M h2so4?

Answers

Answered by Rabiyahasan3

3

Answer:

Explanation:

Given:

H₂SO₄ + 2H₂O ---->2H₃O⁺+ SO₄²⁻

0.05 2X0.05

pH=-log[0.05Mx 2]

pH=-log[0.1M]

pH=1

∴pH of 0.05M of H2SO4 is 1

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